PYTHAGORAS THEOREM

PYTHAGORAS THEOREM 

Objective 

To verify Pythagoras Theorem by performing an activity.

The area of the square constructed on the hypotenuse of a right - angled triangle is equal to the sum of the areas of two squares constructed on other two sides of right angled triangle.

Prerequisite Knowledge 

1. In a right angled triangle the square of hypotenuse is equal to the sum of square on the other two sides.
2. Concept of a right-angled triangle.
3. Area of Square = (Side)²
4. Construction of perpendicular lines. 

Materials Required 

Coloured papers, pair of Scissors, Fevicol, geometry box, sketch pens, 

light coloured square sheet.

PROCEDURE

1. Take coloured paper draw and cut a right angle triangle ACB right angled at C off side 3cm, 4cm and 5cm as shown in figure 1
2. Paste this triangle on white sheet of paper. 
3. Draw squares on each side of the triangle on side AB, BC and AC name them accordingly as shown in figure 2.
4. Extend the sides FB and GA of square ABFG which meets ED at P and CI at Q respectively., as shown in figure 3.
5. Draw perpendicular Aapi on BP which meets CD at R mark the parts 1, 2, 3, 4, and 5 Of the squares BCDE and ACIH colour them with five different colours as shown in figure 4.
6. Cut the pieces 1, 2, 3, 4, and 5 from the squares BCDE and ACIH and place the pieces of square as shown in figure 5

OBSERVATION

Cut pieces of square ACIH and BCDE and completely cover the square ABFG

Area of square ACIH =AC² =  9cm²

Area of square BCDE =BC² = 16cm²

Area of square ABFG =AB² = 25cm²

AB² = BC² + AC²

25   =  9     + 16

RESULT

PYTHAGORAS THEOREM IS VERIFIED